Thumb2: Recognizing doubles #4262
Description
Version and Platform (required):
- Binary Ninja Version: 3.4.4251-dev, 3f761e0a
- OS: ubuntu
- OS Version: 22.10
- CPU Architecture: x86_64
Code below is loading an 8-byte value into a floating point register.
000020792 93ed047b vldr d7, [r3, #0x10] {data_dd908} {0xfefa0000}
Why doesn't BN automatically define a double at data_dd908?
\x00\x00\x00\x00\x00\x008C\x00\x00\xfa\xfeB.v\xbf:;\x9e\xbc\x9a\xf7\x0c\xbd\xbd\xfd\xff\xff\xff\xff\xdf?
HLIL thinks I'm dealing with integers
00002078e q1 = (0 - *(int64_t*)((char*)q1)[8]);
Is this because I implemented VLDR as a regular register load?
case armv7::ARMV7_VLDR:
if (instr->format->operandCount == 3)
{
uint32_t reg = GetRegisterByIndex(instr->fields[instr->format->operands[1].field0]);
il.AddInstruction(WriteILOperand(il, instr, 0, il.Load(4, GetMemoryAddress(il, instr, 1, 4, false))));
il.AddInstruction(il.SetRegister(4, reg, il.Add(4, il.Register(4, reg), ReadILOperand(il, instr, 2))));
}
else
{
il.AddInstruction(WriteILOperand(il, instr, 0, il.Load(4, GetMemoryAddress(il, instr, 1, 4))));
}
break;